如图,在△ABC中,BE是∠ABC的内角平分线,CE是∠ACB的外角平分线,BE、CE...
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共2个回答
热心网友
∠E=180°-∠EBC-∠ECB
=180°-∠ABC/2-∠ACB/2
=180°-(∠ABC+∠ACB)/2
=180°-(180°-∠A)/2
=180°-90°+∠A/2
=90°+∠A/2.
热心网友
1∠A+∠ABE=∠E+∠ACE
2∠A+∠ABC=∠ACD
∠A=∠ACE=∠ACD/2
∠ABC=∠ACD/2
∠A=∠ABC
3∠E=∠A/2
∠A+∠ABC/2=(∠A+∠ABC）/2+∠E
∠E=∠A/2
